Java扑克牌问题
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扑克牌 java 搜索资料
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2、若应用程序的main方法中,定义字符串数组f和s;分别表示扑克牌的牌面值和花色;定义52个元素的Card类型数组deck,用来存放4个花色的52张牌。
如下所示。
String f[] = {"A","2","3","4","5","6","7","8","9","10","J","Q","K"}; String s[] = {"黑桃","红桃","梅花","方块"}; Card deck = new Card[52]; (1)使用Card类的构造方法给deck数组的52张牌赋值,要求数组中先存放黑桃花色的A、2、3、……、K;然后是红桃花色的A、2、3、……、K;梅花花色的A、2、3、……、K;方块花色的A、2、3、……、K。
请写出实现上述功能的程序段。
(2)请编写模拟洗牌的完整程序,即把数组deck中的扑克牌随机打乱存放顺序。
原题如下: 引用内容 private String face; // A, K, Q, J, 10, ... 2 private String suit; // Spade, Heart, Club, Diamond public Card(String suit, String face) { this.face = face; this.suit = suit; } protected String getFace() { return face; } protected String getSuit() { return suit; } public String toString() { return suit + " " + face; }解题,完成程序解: 程序代码package poker;public class Card { private String face; // A, K, Q, J, 10, ... 2 private String suit; // Spade, Heart, Club, Diamond public Card(String suit, String face) { this.face = face; this.suit = suit; } protected String getFace() { return face; } protected String getSuit() { return suit; } public String toString() { return suit + " " + face; } public static void shuffle(Card[] deck, int startIndex, int size, int splitIndex) { //shuffle洗牌 System.out.println("startIndex:" + startIndex); if (splitIndex * 2 > size) { //if rand is 30 Card.swap(deck, startIndex, splitIndex, size - splitIndex); //[52]、0、30、22 shuffle(deck, size - splitIndex, splitIndex, size - splitIndex); //[52]、22、30、22 } else if (splitIndex * 2 < size) { //if rnd is 10 Card.swap(deck, startIndex, size - splitIndex, splitIndex); //[52]、0、42、10 shuffle(deck, startIndex, size - splitIndex, splitIndex); //[52]、0、42、10 } else { Card.swap(deck, startIndex, splitIndex, splitIndex); } } public static void swap(Card[] deck, int srcIndex, int dstIndex, int size) { //交换 //SRC是在本位置显示:source的缩写,源的意思 HREF是点击后连接的目标:HyperlinkReference,超链接引用 String face = ""; String suit = ""; for (int i = 0; i < size; i++) { face = deck[srcIndex + i].face; suit = deck[srcIndex + i].suit; deck[srcIndex + i].face = deck[dstIndex + i].face; deck[srcIndex + i].suit = deck[dstIndex + i].suit; deck[dstIndex + i].face = face; deck[dstIndex + i].suit = suit; } } /** * @param args */ public static void main(String[] args) { //第一问解答 Card[] deck = new Card[52]; String f[] = {"A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"}; String s[] = {"Spade", "Heart", "Club", "Diamond"}; for (int i = 0; i < s.length; i++) { for (int j = 0; j < f.length; j++) { deck[i * 13 + j] = new Card(s[i], f[j]); //依次存入数组之中,每13张一回合 } } //第二问解答 int rnd = 0; int numOfShuffle = 10; for (int i = 0; i < numOfShuffle; i++) { rnd = (int) Math.abs(Math.random() * 52); //Math.random()返回大于或等于 0.0 但小于 1.0 的伪随机 double 值。
Card.shuffle(deck, 0, deck.length, rnd); }// Test /* for (int i=0; i
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